Inactive Tutor answered 09/20/22
Could also multiply both sides by -1
x2 - 160x + 6000 = 0 and factor: (6000 is 100 x 60, not too difficult to find)
(x - 100)(x - 60) = 0
x = 100; x = 60 ,etc.
Edwin W.
asked 09/20/22The profit formula for a small business is p = −x2 + 160x − 6000.
Find the set of x-values that will keep the profit positive. (Enter your answer using interval notation.)
Inactive Tutor answered 09/20/22
Could also multiply both sides by -1
x2 - 160x + 6000 = 0 and factor: (6000 is 100 x 60, not too difficult to find)
(x - 100)(x - 60) = 0
x = 100; x = 60 ,etc.
Inactive Tutor answered 09/20/22
First, you'll want to find the roots of the equation using the quadratic formula:
x = (-b ± √(b2 – 4ac)) / 2a
In your equation:
a = -1
b = 160
c = -6000
Therefore, the roots are:
x = 80 ± 20
so
x = 60 and x = 100
Those roots are the breakeven points for the profit. Therefore, the set of x-values that will keep the profit positive (using interval notation) are written as:
x = (60, 100)
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