∫adt=v(t)=at+C (a is constant). Since v(0)=25.9 km/hr), v(t)=at+25.9.
vdt=x(t)=1/2at2+25.9t+C. Choose x(0)=0 thus C=0 and x(t)=1/2at2+25.9t
Choose v(T)=0 thus a=-25.9/T. Substitute this and solve x(T)=30.5m for T and a ... the Force will be 1280a.
Justin G.
asked 09/15/22A car with a mass m = 1280 kg is moving at a speed s = 25.9 km/h and needs to stop in a distance d = 30.5 m.
a) Write an expression for the magnitude of the net force on the car as it is stopping in terms of the symbols given in the problem statement.
Wouldn't it be |ΣF| = m * s?
b) What is the magnitude of the net force on the car as it is stopping, in N?
∫adt=v(t)=at+C (a is constant). Since v(0)=25.9 km/hr), v(t)=at+25.9.
vdt=x(t)=1/2at2+25.9t+C. Choose x(0)=0 thus C=0 and x(t)=1/2at2+25.9t
Choose v(T)=0 thus a=-25.9/T. Substitute this and solve x(T)=30.5m for T and a ... the Force will be 1280a.
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