Electrochemistry

Question

The following reaction has an average cell potential of 3.00 V: 2 Li(s) + LiI3 3 LiI(aq) How much energy can be derived from a reaction in which 5.00 g of Li is oxidized?

Answer 1

I have been knocked out of my answering your question twice already. I am going to answer tersely and can clarify in follow up:

energy available = -ΔG = n_eFE₀ (Assuming standard states)

Connecting grams of Li to moles of electrons:

5.0 g Li*(1 mole/6.941 g Li)(1 mole e/mole Li)(96485 Coul/mole e)(3 V) = Joules

Coul - volts are joules.

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