Leonard E. answered 09/04/22
Experienced Surgical Resident USMLE Step 1, Step 2 CK and MCAT Tutor
We are told the supplement is 1.6 g in total, and 37.8% of this supplement is calcium by weight. All calcium in the supplement is in the form of CaCO3 (molar mass=100.07 g).
1.6 (0.378) = 0.605 g of Ca
For every 1 mole of CaCO3 (molar mass of 100.07) there is 40.07 g of Ca.
If we use this proportion along with the amount in grams we know we have of calcium (0.605 g), we can determine the grams of CaCO3.
40.07/100.07 = 0.605/X
X=1.51 g of CaCO3