These are all double replacement (partner swapping) reactions. Since none of these are acid/base, they are all driven by precipitation reactions. You need to know a reasonable set of solubility rules.
c) no reaction because the normal rules in general chemistry are that all nitrates and sodium salts are soluble. This means that copper(II) nitrate and sodium sulfate will not form.
a) potassium chloride is soluble because all IA salts are soluble and all chlorides except (lead, silver and mercury) are soluble. Tin(II) phosphate is insoluble and will precipitate. The reaction will look like:
K2PO4(aq) + SnCl2(aq) → 2KCl(aq) + SnPO4(s or cr)
I will leave b for you and it does form a precipitate.