Your program must define and call the following function. The function should return true if the input year is a leap year and false otherwise. (Java)

Question

A common year in the modern Gregorian Calendar consists of 365 days. In reality, Earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are:

1) The year must be divisible by 4

2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400

Some example leap years are 1600, 1712, and 2016.

Write a program that takes in a year and determines the number of days in February for that year.

Ex: If the input is:

1712

The output is:

1712 has 29 days in February.

Ex: If the input is:

1913

The output is:

1913 has 28 days in February.

Your program must define and call the following method. The method should return the number of days in February for the input year.

public static int daysInFeb(int userYear)

Answer 1

Here is a method that performs the functionality of the title.

static boolean isLeapYear(int year)

{

if ((year % 400) == 0) return true; // year divisible by 400

if ((year % 100) == 0) return false; // century year, not divisible by 400

if ((year % 4) == 0) return true; // non-century year, divisible by 4

return false; // year not divisible by 4

}