Nurit H. answered • 07/28/22
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E0=(RT/nF) ln K
0.0275=(8.314)(298)/(2)(96500) lnK
2.14= lnK
K=e^2.14
K=8.52
Andrea M.
asked • 07/28/22What is the equilibrium constant K at 25°C for an electrochemical cell when E° = +0.0275 V and n = 2?(F = 96,500 J/(V･mol), R = 8.314 J/(mol･K))
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