Chem Help please

Question

Given the reaction below, how many liters of Oxygen are required to react with 115.07 g of Ammonia at STP? 

                      4NH₃ + 5O₂   →   4NO + 6H₂O

 Round your answer to two decimal places.

Answer 1

This is a standard stoichiometry calculation except we end with liters of oxygen rather than grams. At STP, you can use 22.4 liters/mole for an ideal gas. Start with the grams of Ammonia:

115.07 g NH₃(1mole/17.03 g NH₃)(5O₂/4NH₃)(22.4 liters/mole O₂ at STP) =

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