A quantity of 42.0 mL of 0.190 M sulfuric acid required 37.0 mL of a potassium hydroxide solution of unknown concentration for complete titration.

Question

Calculate the concentration of the potassium hydroxide solution in moles per liter(M). dry divide-down & multiply up- wet- ______-down &_______ up)

H2SO4(aq). +. 2KOH(aq). ---->. K2SO4(aq). +. 2H2)(I0

Answer 1

.19moles/L x 1L/1000mL x 42 mL = .00798 moles of H2SO4

.00798 moles of H2SO4 x 2 moles of H+/1 mole of H2SO4= .016 moles of H+

in a complete titration .016 moles of H+ = .016 moles of OH-

.016 moles of OH- x 1 mole of KOH/2 mole of OH x 1/37mL x 1000mL/1L = .22 M of KOH