Chemistry - Individual Gas Laws

Question

A gas sample is initially at 41.2 atm and 7.56 L. If the pressure is adjusted to 2.98 atm, what is the new volume of the gas sample? (Assume the sample is maintained in a closed container with constant temperature).

Answer in L

Answer 1

P₁V₁ = P₂V₂

P₁ = 41.2 atm

V₁ = 7.56 L

P₂ = 2.98 atm

Solve for V₂

(41.2)(7.56) = (2.98)V₂

V₂ = (41.2)(7.56)/2.98 = 105 L