Chima M.
asked • 07/08/22Calculate the activation energy, 𝐸a , in kilojoules per mole for a reaction at 52.0 ∘C that has a rate constant of 0.236 s−1 and a frequency factor of 2.01×1011 s−1 . 𝐸a= kJ/mol
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1 Expert Answer
k = Ae-E/RT so, rearranging we get E = -RTln(k/A)
Now, plug in, taking care to express T in Kelving and, if R = 8.314 J/mole-K, then you have to convert to KJ by dividing your result by 1000 J/kJ in order to get kJ/mole.
Chima M.
Is it ok if you can guide me through it if you have time please? I tried using the advice you gave me and it still said it was wrong. Is it ok for can guide me to see what I did wrong? Thank you in advance.
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07/09/22
JACQUES D.
tutor
So, you need to plug into the equation: -(8.314 J/mole-K)*(325.15K)ln(.236 (1/s)/2.01x10^11(1/s)) x 1kJ/1000J. I get 74.3 kJ/mole. Often the calculation problem has to do with units or not using the EE or EXP key (depending on the calculator) 2.01EE11. On a graphing calculator EE is 2nd comma. Take care.
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07/10/22
Chima M.
Thank you so much for taking time out of your day to help me.
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07/10/22
JACQUES D.
tutor
My pleasure. Take care.
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07/10/22
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Chima M.
I meant to put 2,01x 10^11 sorry about that.07/08/22