Potassium Chromate = K2CrO4
Copper (II) Nitrate = Cu(NO3)2
Potassium Nitrate = K(NO3)
Cupric Chromate = CuCrO4
K2CrO4 + Cu(NO3)2 --> K(NO3) + CuCrO4
Balance:
One Chromium atom each side - good
One Copper atom each side - good
Two Potassium on left side and One Potassium on ride side - bad
Multiple K(NO3) by 2 to get two potassium atoms on right side.
K2CrO4 + Cu(NO3)2 --> 2K(NO3) + CuCrO4
One Chromium Each Side - Good
One Copper Each Side - Good
Two Potassium Atoms Each Side - good
Six Nitrogen Atoms Each Side - good
Ten Oxygen Atoms Each Side - good
Reaction is balanced
Answer is: K2CrO4 + Cu(NO3)2 --> 2K(NO3) + CuCrO4
