Raymond B. answered 06/28/22
Math, microeconomics or criminal justice
52 cards, 4 queens, 7 draws
1st draw 48/52 chance of no queen
2nd draw 47/51 chance of no queen
3rd draw 46/50
4th 45/49
5h 44/48
6th 43/47
7th 42/46
chance of no queens in 7 draws is the product of all 7 above
48/52 x 47/51 x 46/50 x 45/49 x 44/48 x 43/47 x 42/46
= 48(47)(46)(45)(44)(43)(42)/(52)(51)(50)(49)(48)(47)(46)
= 45(44)(43)42/52(51)(50)(49)
= 4257/7735
= about .55
= about 55% chance of no queens in 7 draws