How many moles of solute are present in the following solutions? 110 mL of 0.17 M NaHCO3

Answer 1

Josh,

Remember the molarity 0.17 M is telling you how many moles of the solute (compound NaHCO₃ is in 1 liter (1000 mL) of the solution. 110 mL = 0.110 L of solution. If you know how many moles is present in 1 liter of solution (molarity), you can calculate the moles present in 0.110 L.

Bear in mind significant figures given your answer should have 2 sig. figures

Beginning with what is given

0.110 L soln x (0.17 mol NaHCO₃ ⁄ 1 L soln = 0.0187 mol [ 0.019 mol ] reported answer