General Chemistry 2

Question

The solubility of Ba(OH)2 is expected to be (higher/lower/equal) in a solution of BaNO3 than in pure water. This is because the BaNO3 solution contains (barium ions/lower ph/nitrate ions) that (prohibit/maintain/inhibit) further dissociation of Ba(OH)2 into Ba2+ and OH− . Hint: Consider LeChatelier's principle.

Answer 1

The equilibrium equation for the the dissociation of Ba(OH)₂ is Ba(OH)₂(s) ⇔ Ba²⁺ + 2(OH^-)

By LeChatelier's principle adding Ba²⁺ or OH^- (Increasing pH) would move the equilibrium away from the products and towards precipitation. Barium nitrate dissolves completely and adds Barium ions to the solution.