How many grams of CO2 are formed from the combustion of 22.7 moles of C8H18?

Question

Octane burns according to the following balanced equation:

2C8H18 + 25O2 --> 18H2O + 16CO2

How many grams of CO2 are formed from the combustion of 22.7 moles of C8H18?

Answer 1

Standard stoichiometry problem except we start with moles, rather than grams:

Start with what you know and multiply with the proper relations in order to get the grams of CO₂. The usual process is grams of i to moles of i to moles of j to grams of j. In this case we only need 2 steps:

22.7 moles Oct *(16 CO₂/2 Oct)(44 g CO₂/mole) = g CO₂