Inactive Tutor answered 05/27/22
Tutor
New to Wyzant
225 = 10D +5N
D=2N
225 = 10(2N) + 5N = 25N
N = 225/25 = 9 Nickels
D = 2N = 2(9) = 18 Dimes
18(10) + 5(9) = 180+45 = 225
Aurora F.
asked 05/27/22pudge had $2.25 in dimes and nickels if he had twice as many dimes as nickels, how many of each coin did he have?
Inactive Tutor answered 05/27/22
225 = 10D +5N
D=2N
225 = 10(2N) + 5N = 25N
N = 225/25 = 9 Nickels
D = 2N = 2(9) = 18 Dimes
18(10) + 5(9) = 180+45 = 225
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