The one-to-one functions g and h are defined as follows.

Question

g^-1(x)=

(g * g^-1)(7)=

h^-1(0)=

Answer 1

g(g^-1(x)) = x = g^-1(g(x)) for any value of x

g(g^-1)(7)) = 7 = g^-1(g(7))

h(h^-1(x)) = x = h^-1(h(x)) for any value of x

h(h^-1)(0)) = 0 = h^-1(h(0))

f(f^-1(x)) = x = f^-1(f(x)) regardless what value of x

inverse functions are similar to inverse arithemetic operations

x times 3, divided by 3 = 3x/3 = x

x + 4 -4 = x

whatever the function does to x, the inverse function reverses it and brings you back to x