How many moles of oxygen of are needed to produced 5.3 moles of aluminum oxide ?

Question

4AL+3O2=2AL2O2

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Answer 1

the balanced chemical equation that you have there

4Al + 3O2 ​→ 2Al2​O3​

means that the mole ratio is 3 mol O2: 2 mol Al2O3

from there then you can just scale it over

5.3 mol Al2O3 x 3 mol O2 / 2 mol Al2O3 = 7.95 mol O2

meaning that 7.95 moles of oxygen are needed to produce 5.3 moles of aluminum oxide

Answer 2

You can easily reach out if you have any more questions.

1.  Step 1. Find the mole-to-mole ratio between O₂ and Al₂O₃

From the chemical reaction I see that there are 3 O₂/2 Al₂O₃

1. Step 2. Calculate moles

moles of O₂= 5.3 mol of A₂O₃* 3 mol of O₂/2 mol of Al₂O₃ = 7.95 = 8.0 mol of O₂

Also, you chemical reaction is not balanced fully: 4Al + 3O₂ → 2Al₂O₃

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