Roger N. answered 05/17/22
. BE in Civil Engineering . Senior Structural/Civil Engineer
Solution:
The centripetal acceleration is the normal acceleration that will push the car out of the circle and make it skid
an = V2/ r where V is the speed of car that will keep the car from skidding out of the circle, an = 0.6 g = 0.6 ( 9.81 m/s2) = 5.87 m/s2
The radius of the circle r is 1/2 the diameter = 24 m /2 = 12m
equating 5.87 m/s2 = V2 / 12 m, V2 = 12 m ( 5.87 m/s2) = 70.44 m2/s2 and V = 8.39 m/s