
Nurit H. answered 05/17/22
MD student with 8+ years tutoring experience
combustion of octane:
2C8H18 + 25O2 ––> 16CO2 + 18H2O
first we must convert gallons of octane into mL
24 gallons X (3.785L/1 gallon) X (1,000ml/L)= 9.084 E4 mL
next we use the density to turn mL into grams and the molar mass to turn grams into moles
9.084E4 mL X (.692g/1mL) X (1mol/114.23g)= 550.30447 moles
next we use the balanced equation to convert moles of octane into moles of CO2
550.30447 mols octane X (16mol co2/ 2 mol octane)= 4.4024E3 moles co2
lastly, we convert moles of Co2 into lbs
4.4024E3 mols X (44.01 g/mol) X (1kg/1000g) X (2.20462 lbs/1kg)= 427.15 lbs co2