Sa M.
asked 05/13/22Maximum number of unpaired electrons
What is the maximum number of unpaired electrons possible in an octahedral complex?
1 Expert Answer
Michael S. answered 08/05/26
B.S. in Chemistry, Indiana University; Organic Chem Teaching Intern
Five — achieved by a high-spin d5 complex.
Why 5 is the ceiling
An octahedral field splits the five d orbitals into two sets:
• t2g — three orbitals, lower energy
• eg — two orbitals, higher energy
Three plus two is five orbitals, and by the Pauli principle each holds at most one unpaired electron. So five is a hard structural limit — adding a sixth d electron has nowhere to go but into an already-occupied orbital, where it must pair up and cancel a spin.
Why d5 high-spin reaches it
When the splitting energy Δo is smaller than the pairing energy — a weak-field ligand — electrons prefer climbing into the higher eg set over doubling up. By Hund's rule they occupy all five orbitals singly with parallel spins:
t2g: ↑ ↑ ↑ eg: ↑ ↑ → 5 unpaired
Real examples: [Mn(H2O)6]2+ and [FeF6]3−, both d5 with weak-field ligands.
Everything else falls short
d4 high-spin: 4 unpaired — not enough electrons.
d6 high-spin: 4 unpaired — the sixth electron must pair into t2g, cancelling one.
d5 low-spin: only 1 unpaired (t2g5), because a strong-field ligand like CN− makes Δo large enough that pairing costs less than promotion. [Fe(CN)6]3− is the classic case.
So d5 is the peak of the curve, and it only delivers 5 in the high-spin case. Same electron count, same geometry, completely different magnetism — the ligand decides.
How this is measured
Unpaired electrons make a complex paramagnetic, and the magnetic moment follows μ = √(n(n+2)) Bohr magnetons. For n = 5 that is √35 = 5.92 BM, the largest value any octahedral d-block complex can show. Measuring μ is how chemists distinguish high-spin from low-spin experimentally.
One footnote in case your course covers it: this ceiling of 5 applies to d-block complexes. Lanthanides and actinides use f orbitals — seven of them — so an f7 ion such as Gd3+ carries 7 unpaired electrons. But for a standard octahedral transition-metal complex, the answer is 5.
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Sa M.
Would it be two?05/13/22