Can someone please answer this forme

Question

What is the molarity of a solution that contains 112 g of NaCl in 6 L of solution?

 ______M

Answer 1

Na - 23g/mol

Cl - 35.5g/mol

NaCl - 58.5 g/mol

n = 112/58.5

n = 1.91 mol of NaCl in 112 g

M= n/V

M=1.91/6

M=0.32 mol/L

Answer 2

You need to use the molar mass of NaCl to determine how many moles there are in 112g.

Looking up Na on the periodic table, it has a molar mass of 22.99 g/mol. Looking up Cl, it has a molar mass of 35.45 g/mol. So NaCl has a molar mass of 22.99 + 35.45 = 58.44 g/mol.

Dividing 112 g by 58.44 g/mol results in 1.916 moles

The molarity is the number of moles per liter so 1.916/6 = 0.3 M