This is a variation on the combined gas law. While we generally don't include the moles (n) we can because P ∝n.
So, P1V1/n1T1 = P2V2/n2V2
We're told that the P & T are constant, so they cancel and we can rearrange to solve for (isolate) n2:
n2 = n1V2/V1. This gives an answer, to 3 sig figs, of 104 moles