Considering the respective partial pressures, what is the free energy for this reaction?

Question

At 1120 K, ∆G° = 69.3 kJ/mol for the reaction 3 A (g) + B (g) →2 C (g). If the partial pressures of A, B, and C are 11.5 atm, 8.60 atm, and 0.510 atm respectively, what is the free energy for this reaction?

Answer 1

The dependence of delta G on partial pressures can be found from

ΔG = ΔG₀ + RTlnQ = ΔG₀ + RTln(P_C²/(P_A³P_B)

= 69300 J/mole + 8.314 J/Mole-K * (1120K)*ln(.510²/((11.5³)(8.60)))