Find h(-2), h(0), and h(4)

Question

find h(-2), h(0), and h(4) for the following function: h(x)=6x^2 + 3

Answer 1

h(x) = 6x^2 +3

h(0) = 6(0^2) + 3 = 0 + 3

h(3) = 3

h(-2) = 6(-2)^2 + 3 = 6(4) +3 = 24+3 = 27

h(-2) = 27

h(4) = 6(4)^2 +3 = 6(16) + 3 = 96+3 = 99

h(4) = 99