HELP WITH GAY LUSSAC CHEM

Question

if the pressure of a ballon is 780 torr at a room temp of 20 c whats the pressure of the balloon if the temp rises to 40 c

Answer 1

Gay-Lussac's Law teaches us that the pressure of a gas increases as its temperature increases. The equation, P₁/T₁ = P₂/T₂ can help solve your problem. (Note that the temperature must be converted into Kelvin, K, by adding 273 to your temperature in degrees Celsius.)

The initial pressure, P₁ = 780 torr

The initial temperature, T₁ = 20°C = 293K

The final temperature, T₂ = 40°C = 313K

You can plug all of these values into the equation and solve for P₂:

(780 torr)/(293K) = P₂/(313K)