HELP WITH CHARLES LAW PLS

Question

A 15.0L balloon at room temperature (293.15k) is placed in a oven what is the temperature of the oven if the ballons new volume is 30.0L

Answer 1

Christine,

To solve this problem, you'd use the equation V₁/T₁ = V₂/T₂

The 1's represent the initial conditions and the 2's are the conditions after something has been done to the balloon.

For this question, we can list what we have so we know exactly where they fit in the equation we're going to use to solve the problem.

V₁ = 15.0L

V₂ = 30.0 L

T₁ = 293.15 K

T₂ = ??? K (our unknown, the oven's temperature)

If we plug the numbers in the places they belong in the equation, we have:

15.0L/293.15 K = 30.0L/T₂

0.0512 L/K = 30.0 L/T₂

T₂ = 30.0 L ÷ 0.0512 L/K

T₂ = 586 K

If you need to convert the temperature to Celsius, subtract 273.15.

The answer is reasonable because volume and temperature are directly proportional to each other. The volume doubled, from 15.0 L to 30.0L, and so did the Kelvin temperature, 293 K (approximately) to 586 K.

Hope this helps.