n=6, F= 96500 and you need standard emf of the cell and multiply all three.
6* 96500* 3.87
The answer is 2240.73 Kj
Standard emf of the cell is 3.87 which is obtained by subtracting Mg value from Au value
Mg= -2.37 and Gold value = +1.5
Chima M.
asked • 04/29/22Calculate the standard free-energy change for the reaction at 25 ∘C. 2Au3+(aq)+3Mg(s)↽−−⇀2Au(s)+3Mg2+(aq)
Delta G= ?kJ
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