assuming the gasses are ideal gasses,
PV=nRT
(205 atm)(1000L)=n(8.314 J/molK)(698K). where n=moles
n=35.325
Since we are told nitrogenous makes up 25% of the mixture,
35.325*.25=8.83 mol Nitrogen
We know Nitrogen exits as N2 naturally so
8.83 mol*28g/mol= 247.27 g
247.27/1000= 0.24727 Kg