The nuclear mass of Ti48 is 47.9359 amu. Calculate the binding energy per nucleon for Ti48 .

Question

 Δ𝐸per nucleon:_____ J/nucleon

Answer 1

Given mass of Titanium 48, m = 47. 9359 amu. Atomic number A = 48

Assume mass of proton = 1.007825 amu, mass of neutron = 1.008665 amu

From periodic table Charge number Z for Titanium = 22

Number of neutrons N = A - Z = 48 -22 = 26

Binding energy of Titanium nucleus E = (Z x proton mass + N x neutron mass - m) x c^2

Substitute values E = (22 x 1.007825 + 26 x 1.0008665 - 47.9359 x 48) x c^2

= 0.4615 x c^2 amu

= 0.4615 c^2 x 931.5 Mev/c^2

= 429.92 MeV

Binding energy per nucleon = E/A = 429.92/48 = 8.9568 Mev/Nucleon

I hope this helps.

Sincerely,

Shailesh (Sky) Kadakia, Expert Tutor

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