What is the pressure in atm of 6.07 moles of acetylene gas in a 56.26 L cylinder at 37oC?

Question

solution to the problem

Answer 1

Use the Ideal Gas Law:

PV = nRT

or, solving for P, P = nRT/V

If you use R = 0.082057 L•atm/(mol•K) then you can use V = 56.26 L, n = 6.07 moles, and T = (37 + 273.15) K = 310.15 K

So P = (6.07)(0.082057)(310.15)/56.26 = 2.7 atm