What is the pressure in atm of 6.07 moles of acetylene gas in a 56.26 L cylinder at 37oC?

Question

solution to the problem

Answer 1

To solve this problem, let's first define the variables given in the problem:

n = 6.07 moles

V = 56.26 L

T = 37°C = 310K

P = ???

With these variables defined, we can plug them in to the Ideal Gas Law Equation, PV = nRT

R is a gas constant dependent on the units of measurement of pressure (in this case, atm)

R = 0.0821 L·atm/mol·K (notice that temperature is in Kelvin, not Celsius)

When all of these variables are plugged in to the equation, your units of measurement will cancel out, leaving you with the pressure in atm.

P • (56.26L) = (6.07mol) • (0.0821 L·atm/mol·K) • (310K)