A 678 mL gas sample at STP is compressed to a volume of 263 mL, and the temperature is increased to 38◦C. What is the new pressure of the gas in Pa? Answer in units of Pa.

Answer 1

Case 1 V₁ = 678 ml, P₁ = 1 atm, T₁ = 273.15 K (must be absolute units)

Case 2: V₂ = 263 ml, P₂ = ? , T₂ = 311.15 K

I like to think in terms of multipliers (either direct or inverse (T is proportional to P, V is inversely proportional to P):

P₂ = P₁(T₂/T₁)(V₁/V₂) If you want Pascals, just put P₁ in Pascals: 1.013 x 10⁵ Pa.