Anthony T. answered 04/19/22
Patient Science Tutor
AgBr is less soluble than AgCl and will precipitate first. When AgCl just begins to precipitate, the Ksp of AgCl can be used to determine the silver ion concentration at that point.
Ksp = [Ag+] [Cl-]
1.8 x 10-10 = [Ag+] x 0.115
[Ag+] = 1.8 x 10-10 / 0.115 = 1.57 x 10-9
At this point, the concentration of bromide still in solution can be obtained from the Ksp of AgBr.
Ksp = [Ag+] [Br-]
5.0 x 10-13 = 1.57 x 10-9 x [Br-]
[Br-] = 5.0 x 10-13 / 1.57 x 10-9 = 3.18 x 10-4 M. This is the concentration of Br- still in solution.
%Br- in solution = 3.18 x 10-4 / 0.264 x100 = 0.12%
Dilute ammonia solution will dissolve AgCl but not AgBr.