A 25.00 mL aliquot of HCl of unknown concentration is titrated with 25.62 mL of 0.1011 M NaOH. What is the molarity of the HCl solution?

Answer 1

1. Convert the mL of NaOH to liters 25.62mL NaOH = 0.02562L NaOH and 0.025L HCl
2. Convert the molar concentration of NaOH to moles by 0.1011M * 0.02562L = 0.00259 mol HCl
3. We know the chemical equation is HCl + NaOH -> NaCl + H2O
4. balanced equation
5. Then we just find the concentration of HCl
6. 0.00259 mol / 0.025 L = 0.104M HCl

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