chemistry question, please help

Question

Liquid octane CH3CH26CH3 will react with gaseous oxygen O2 to produce gaseous carbon dioxide CO2 and gaseous water H2O. Suppose 2.3 g of octane is mixed with 2.00 g of oxygen. Calculate the maximum mass of carbon dioxide that could be produced by the chemical reaction. Be sure your answer has the correct number of significant digits. g

Answer 1

1) You need to write the equation: C₈H₁₈ + 25/2 O₂ → 8CO₂ + 9H₂O

2) There are several ways to solve this. The easiest, brute force way is to calculate the CO₂ produced assuming the octane is the limiting reactant and the oxygen is the limiting reactant. Whichever gives you less CO₂ is the LR and the amount of CO₂ is the answer.

2.3 g Oct (mole/114.23 g Oct) (8CO₂/1 Oct)(44.01 g/mole CO₂) = g CO₂

Do the same for oxygen. Note that Octane data is 2 SFs and Oxygen data is 3 SFs.