Can someone help me complete the table plz

Question

[H3O+] [OH-] pOH pH

1.0*10^-8 1.0*10^-6 6.00 8.00

______ _______ ____ 3.05

9.7*10^-9 ______ ____ ____

_______ _______ _____ 13.79

_______ 9.6*10^-11 _____ _____

Part A

Complete the first column of the table

[H3O+]=

Part B

Complete the second column of the table.

[OH-]=

Part C

Complete the third column of the table.

pOH=

Part D

Complete the fourth column of the table.

pH=

Answer 1

use these equations. There are multiple ways to solve them, but you'll arrive at the same answer.

FIRST make sure your calculator can do the following:

if you enter:

log₁₀(0.01)

the answer should be "-2"

if you enter:

-log₁₀(1×10^-5)

the answer should be "5"

if you enter:

10^-5.37

the answer should be "0.00000426579518802" which is equal to "4.26579518802×10^-6"

Okay, now, use these 6 equations:

1. pH= -log₁₀[H⁺]
2. note, for all of these equations, [H₃O⁺] and [H⁺] are conceptually and mathematically identical.
3. [H⁺]=10^-pH
4. pOH= -log[OH^-]
5. [OH^-]=10^-pOH
6. pH+pOH=14
7. [H⁺][OH^-]=10^-14

^{Those equations will solve all of your problems.}