N2 + 3 F2 → 2 NF3 How many molecules of NF3 will be created if 42.1 grams of N2 react?

Answer 1

42.1g N₂ x 1 mole N₂ x 2 moles NF₃ x 6.02 x10²³ molecules NF₃ = 1.81 x 10²³ molecules NF₃

28.02g N₂ 1 mole N₂ 1 mole NF₃