Full answer and explanation to question in description would be greatly appreciated.

Question

A 100g brass block is heated from room temperature (24 C) to 80 C and placed in contact with an identical brass block at room temperature, in order to increase its temperature. Calculate the final temperature when the blocks reach thermal equilibrium.

Answer 1

Loss of heat energy by mass1 is dQ1 = = m1 c1 ( 80 - T)

Gain of heat energy by mass2 is dQ2 = m2 c2 ( T - 24))

m is mass, kg

c is the specific heat

T is the final, equilibrium temperature, oC

dQ1 + dQ2 = 0 by conservation of energy

m1 = m2, c1 = c2 for identical blocks, so

(80-T) = (T-24)

2T = 104

T = 52 oC