J.R. S. answered 03/23/22
2KCl(s) --> 2K(s) +Cl2(g) Δ𝐻=873 kJ
18.3 g KCl x 1 mol KCl / 74.55 g x 873 kJ / 2 mol KCl = 214 kJ
Crystal R.
asked 03/23/22How much heat is absorbed when 18.3g of KCl decomposes to K and Cl2 Show the conversions required to solve this problem.
2KCl(s) --> 2K(s) +Cl2(g) Δ𝐻=873 kJ
18.3 g KCl x(--------) x(---------) = ________
Answer Bank
70.90 mol Cl2 39.10 g K 2 mol KCl 1 mol K
2 mol K 74.55 g KCl 1 mol Cl2 1 mol KCl
873 kJ
J.R. S. answered 03/23/22
2KCl(s) --> 2K(s) +Cl2(g) Δ𝐻=873 kJ
18.3 g KCl x 1 mol KCl / 74.55 g x 873 kJ / 2 mol KCl = 214 kJ
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