How many milliliters are there in a solution containing 65.6g of KOH if the solution is 1.80M

Answer 1

Lydia,

This calculation involves the molarity equation M = mol/L.

1.80 M means 1.80 mol/L

What we need to do is look at the equation to see what we have that we can use.

We have a mass and we have molarity, M. so not much that matches the formula. However, we can convert the mass to moles by using the molar mass of the KOH.

Mass/molar mass = moles

65.6 g x 1mole/56.11 g = 1.17 moles of KOH

Now, we have moles and molarity. If we rearrange the equation, volume (in L) = moles/M

1.17 moles x 1 L/1.80 mol =0.650 L

To convert L to mL --------- 0.65 L x 1000 mL/1 L = 650. mL