Raymond B. answered 08/06/23
Math, microeconomics or criminal justice
12C7= 12!/5!7! = 12x11x10x9x8/5x4x3x2=132x6= 792
12P7= 12!/5!=12x11x10x9x8x7x6= 132x720x42= 3991680= almost 4 million
=7!(12C7)=7x6x5x4x3x2x792= 210x24x792=3,991,680
Natasha B.
asked 03/21/22Suppose we want to choose 7 objects without replacement from 12 distinct object. How many times can this be done if the order of choices does not matter? How many times can this be done if the order of choices matter?
Raymond B. answered 08/06/23
Math, microeconomics or criminal justice
12C7= 12!/5!7! = 12x11x10x9x8/5x4x3x2=132x6= 792
12P7= 12!/5!=12x11x10x9x8x7x6= 132x720x42= 3991680= almost 4 million
=7!(12C7)=7x6x5x4x3x2x792= 210x24x792=3,991,680
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