The plates of a parallel-plate capacitor are 2.50mm apart, and each carries a charge of magnitude 80.0nC.

Question

The plates of a parallel-plate capacitor are 2.50mm apart, and each carries a charge of magnitude 80.0nC. The plates are in vacuum. The electric field between the plates has a magnitude of 4.00x106V/m. What is the potential difference between the plates? (SHOW YOUR SOLUTIONS)

A. 2.00x10⁴ V

B. 1.75x10⁴ V

C. 1.00x10^-4 V

D. 1.00x10⁴ V

Answer 1

E=V/d thus V=E*d = 4E6*2.5E-3=1E4