SiO2 + 2C → Si + 2CO balanced equation
SiO2 = 60 g/mol
Si = 28g/mol
C = 12 g/mol
CO = 28 g/mol
PART A
60g of SiO2 reacts with 24g of C, so 59.8kg of SiO2 should react with:
60/24 = 59.8/x
x = 23.92 kg of C
Since you have 25.8 kg of C, the limit reagent is SiO2
PART B
60g of SiO2 produces 28 g of Si, so 59.8kg of SiO2 should produce:
60/28 = 59.8/y
y = 27.91 kg of Si
PART C
Since 27.91 kg is the theoretical yield, 22.4 kg is:
22.4/29.91 = 0.803
So, the percent of the reaction is:
80.3%