When calcium carbonate is added to hydrochloric acid, calcium chloride, carbon dioxide, and water are produced. CaCO3(s)+2HCl(aq)⟶CaCl2(aq)+H2O(l)+CO2(g)

Question

When calcium carbonate is added to hydrochloric acid, calcium chloride, carbon dioxide, and water are produced.

CaCO3(s)+2HCl(aq)⟶CaCl2(aq)+H2O(l)+CO2(g)

How many grams of calcium chloride will be produced when 26.0 g

of calcium carbonate is combined with 15.0 g

of hydrochloric acid?

mass of CaCl2:________?_______g

How many grams of the excess reactant will remain after the reaction is complete?

mass of excess reactant:________?_______g

Answer 1

26g CaCO₃ x 1 mole CaCO₃ x 1mole CaCl₂ x 111g CaCl₂ = 28.8g CaCl₂

100.1g CaCO₃ 1mole CaCO₃ 1 mole CaCl₂

15g HCl x 1 mole HCl x 1 mole CaCl₂ x 111g CaCl₂ = 22.8g CaCl₂

36.5g HCl 2 moles HCl 1 moles CalCl₂

The lowest amount tells you the maximum amount (theoretical yield) of the product that can be produced.

Therefore the amount of CaCl₂ that can be produced in this reaction is 22.8g.

Since HCl yielded the least amount of product, then HCl is the limiting reactant. Therefore, CaCO₃ is the excess reactant

To find the amount of excess CaCO₃. Use HCl to find how much of the CaCO3 was used in the reaction.

15g HCl x 1 mole HCl x 1 mole CaCO₃ x 100.1g CaCO₃ = 20.6g CaCO₃

36.5g HCl 2 moles HCl 1 mole CaCO₃

20.6g of CaCO₃ was used up in the reaction

Excess amount of CaCO₃ = 26g - 20.6g

The excess amount of the reactant (CaCO₃) that will remain after the reaction is complete is 5.4g.