Anonymous A. answered 03/13/22
Discrete Math Background
Let x be any set.
Suppose ¬(x⊄A ∧x⊄B). Then x⊆A or x⊆B, by DeMorgan's Law.
If x⊆A, then x⊆AUB, since A⊆AUB. Thus, x∈Ρ(AUB), since x⊆AUB.
If x⊆B, then x⊆AUB, since B⊆AUB. Thus, x∈Ρ(AUB), since x⊆AUB.
In either case, x∈Ρ(AUB), which completes the indirect proof.