Jacob W. answered 03/10/22
BSE Chemistry, Chemistry Teacher
C1V1 = C2V2
You have C1 = 10.3 M
You have V1 = 25.3 mL
You have V2 = 150 mL
Just plug in and solve!
10.3M * 25.3mL = C2 * 150 mL
260.59= C2 * 150 mL
260.59/150= C2
1.73M = C2
Aaron M.
asked 03/10/22In the laboratory, a student dilutes 25.3 mL of a 10.3 M hydrobromic acid solution to a total volume of 150.0 mL. What is the concentration of the diluted solution?
Concentration = M
Jacob W. answered 03/10/22
BSE Chemistry, Chemistry Teacher
C1V1 = C2V2
You have C1 = 10.3 M
You have V1 = 25.3 mL
You have V2 = 150 mL
Just plug in and solve!
10.3M * 25.3mL = C2 * 150 mL
260.59= C2 * 150 mL
260.59/150= C2
1.73M = C2
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