Make 25mL of 0.25M solutions of sodium chloride, sucrose and magnesium sulfate

Question

It’s a Chemistry lab where we have to figure out what to do the question above is the only context we get plus what we have learned.

Answer 1

I can answer this in a general way. First, calculate the number of moles of the substance that would be in 25 mL of a 0.25 M solution.

The formula for this is 0.25 moles/L x 25 mL / 1000 mL/L = 6.25 x 10^-3 moles.

Determine the molecular mass of each substance; call it M g/mole.

Now use the formula M g/mole x 6.25 x 10^-3 moles. This gives you the mass of each substance to be dissolved in sufficient water to make 25 mL of the solution.