15 g Fuel * (1 mole/g)*(11 moles O2/1 mole fuel) = moles O2 (Find g/mole using formula mass)
moles O2 *(22.4 liters/mole at STP) = liters O2
moles O2 * (7 CO2/11 O2) * (44 g/mole CO2) = g CO2
Michael S.
asked 03/07/22Using the balanced equation from question 4 above for unknown fuel/additive that was analyzed by GC-MS, what volume of oxygen (at STP) would be needed to completely react with 15.0 g of your fuel? How many grams of CO2 could be produced?
Moles of O2 needed (mol):____
Volume of O2 needed (L):______
Grams of CO2 produced (g):____
15 g Fuel * (1 mole/g)*(11 moles O2/1 mole fuel) = moles O2 (Find g/mole using formula mass)
moles O2 *(22.4 liters/mole at STP) = liters O2
moles O2 * (7 CO2/11 O2) * (44 g/mole CO2) = g CO2
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Michael S.
Thank you!03/07/22